<body><script type="text/javascript"> function setAttributeOnload(object, attribute, val) { if(window.addEventListener) { window.addEventListener('load', function(){ object[attribute] = val; }, false); } else { window.attachEvent('onload', function(){ object[attribute] = val; }); } } </script> <div id="navbar-iframe-container"></div> <script type="text/javascript" src="https://apis.google.com/js/platform.js"></script> <script type="text/javascript"> gapi.load("gapi.iframes:gapi.iframes.style.bubble", function() { if (gapi.iframes && gapi.iframes.getContext) { gapi.iframes.getContext().openChild({ url: 'https://www.blogger.com/navbar.g?targetBlogID\x3d5991736482202189474\x26blogName\x3dP+A+Q\x26publishMode\x3dPUBLISH_MODE_BLOGSPOT\x26navbarType\x3dBLUE\x26layoutType\x3dCLASSIC\x26searchRoot\x3dhttps://physicsanswerquestion.blogspot.com/search\x26blogLocale\x3den\x26v\x3d2\x26homepageUrl\x3dhttp://physicsanswerquestion.blogspot.com/\x26vt\x3d-295596038200979243', where: document.getElementById("navbar-iframe-container"), id: "navbar-iframe" }); } }); </script>

P A Q

Physics Answer Questions

Will a hot air balloon still rise if the surrounding air is the same temperature?

Q : If the air temperature outside of the hot air balloon and the air inside the hot air balloon are the same, will that balloon still rise or just remain at the same point. This is not to say both temperatures are cold. Both temps should be hot. Hot enough for the air to rise, but if the outside and inside are equal in the heat, will that big a/s/s balloon move or just stay in the same spot. I think this would be difficult to try because a hot air balloon is very large and to heat all the surronding air around it might be next to impossible. This only applies to hot air. Not other types of gasses lighter than air, were temp wont affect lift dramatically. The reasonig for this question is for exploration on other planets with hot air temps, would this type of situation work using only air? And would it be possible to control it?

A: A balloon filled with hot air rises because of the force of buoyancy. That means the density of air inside is lesser than the surrounding air (because hot air expands thus density decreases) and thus there is an upthrust acting on the balloon. Now, if the surrounding air is at the same temperature then its density is same as that inside the balloon and so the balloon will not rise. But the balloon will not not remain at the same point. it will fall because of the weight of the rubber in it.
In case of exploration on other planets, firstly other planets have very low density of air in the atmosphere (most of them do not have any air) and secondly even then is one wants to use this one has to heat up the balloon to a temperature for which the density decreass lower than the surrounding. Hope this answers your question.

Labels: ,

« Home | Next »
| Next »
| Next »
| Next »
| Next »
| Next »
| Next »
| Next »
| Next »
| Next »

»

Post a Comment